Tentukan persamaan jika di ketahui panjang suatu minor= 8 dan titik fokus(1,-6),dan(1,4)

Jawaban: 1

Jawaban

  • Jawaban diposting oleh: vara201
    Fokus1 (1,-6) ==> (p,q+c)
    fokus2 (1,4) ==> (p, q-c)

    q + c =-6
    q - c = 4
    -
    2c = -10
    c = -5

    q +c = -6
    q -5= - 6
    q = -1
    minor 8 :
    2b = 8
    b = 4
    a^2 = c^2-b^2
    = -5^2 - 4^2
    = 25 -16
    =9

    (y-q)^2 / a^2 - (x-p)^2 /b^2
    =(y-(-1)) ^2 / 9 - (x-1)^2 / 4^2
    =(y+1) ^2 /9 - (x-1)^2 / 16
    maap klo salah
  • Jawaban diposting oleh: yasmin7718
    Fokus 1 (1,-6) ==> (p, q +c)
    fokus 2 (1,4) ==> (p, q-c)

    q +c = -6
    q-c = 4
    -
    2c = -10
    c = -5
    q+ c = -6
    q -5 = -6
    q = -1

    minor 8 :
    2b = 8
    b = 4
    a^2 = c^2 -b^2
    = -5^2 - 4^2
    = 25 -16
    = 9
    persamaan :
    (y-q) ^2 / a^2 - (x-p)^2 / b^2
    = (y-(-1)) ^2 / 9^2 - (x-1)^2 / 4^2
    = (y+1)^2 /81 - (x-1)^2 / 16
    maap klo salah
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Tentukan persamaan jika di ketahui panjang suatu minor= 8 dan titik fokus(1,-6),dan(1,4)...